转发一份php招聘信息

<?php

/**
* SF后端开发者招聘函数
*
* @param array $conditions 条件列表
* @return boolean 是否合格
*/
function wanted_developer(array $conditions) {
    $score = 0;

    foreach ($conditions as $key => $condition) {
        switch ($key) {
            case 'skills':
                foreach ($condition as $name => $rank) {
                    switch ($name) {
                        case 'linux':
                        case 'nginx': oleou.com
                        case 'apache':
                            $score += $rank * 1;
                            break;
                        case 'html':
                        case 'php':
                        case 'java':

oleou